Posted by **Butch** on Sunday, July 24, 2011 at 1:26pm.

Write an equation in point slope form for the perpendicular bisector of the segment with endpoints A(-3,-3) and B(5,6)

- Geoemetry -
**Henry**, Sunday, July 24, 2011 at 7:44pm
A(-3,-3), M(x,y), B(5,6).

x = (-3+5) / 2 = 1.

y = (-3+6) / 2 = 1 1/2 = 3/2.

The slope of a straight line is the same at all points on the line.

m = (6-(-3)) / (5-(-3)) = 9/8.

m2 = -8/9 = Negative reciprocal of m.

(1,3/2),(x,y),

m2 = (y-3/2) / (x-1) = -8/9,

Cross multiply:

y-3/2 = -8/9(x-1).

- Geoemetry -
**Jacksom**, Wednesday, April 1, 2015 at 11:49pm
write an equation in point-slope form for the perpendicular bisector of the segment with the given end points M(-5,4),N(1,-2)

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