Posted by falcon306 on Saturday, July 23, 2011 at 5:45pm.
Torque = (moment of inertia) x (angular acceleration) = 50 N*m
The moment of inertia is
I = (1/2) M*R^2 = 281.25 kg*m^2
The maximum angular velocity you want to achieve is
w = 1200 rev/min * (2 pi/60) = 125.66 rad/s
The angular acceleration rate is
alpha = 125.66 rad/s / t
where t is the time required.
alpha = 50/281.25 rad/s^2 = 125.66/t
Solve for t in seconds
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