Posted by **Kate** on Saturday, July 23, 2011 at 10:34am.

Identify the period in degrees and radians:

y = sin2x:

y = cos(3/2)x:

y = 2sin(1/2)x:

y = 1.5cos0.25x:

- Math -
**Reiny**, Saturday, July 23, 2011 at 11:26am
The period of a sine or cosine curve

= 360°/k , where k is the coeffiecient of the angle

e.g. your 1st question

y = sin 2x , k = 2

period = 360°/2

= 180°

or in radians:

period = 2π/k = 2π/2 = π

do the others the same way.

## Answer This Question

## Related Questions

- Math - Solving Trig Equations - What am I doing wrong? Equation: sin2x = 2cos2x ...
- trig - 2sin(x)cos(x)+cos(x)=0 I'm looking for exact value solutions in [0, 3&#...
- math - Sin(2x)=2sin(x)cos(x) find the exact value in radians with 2sin^2(x)+sin^...
- math - Sin(2x)=2sin(x)cos(x) find the exact value in radians with 2sin^2(x)+sin^...
- advanced functions - Prove that 2sinxsiny = cos(x-y) - cos(x+y) Prove that sin2x...
- calc - Where do I start to prove this identity: sinx/cosx= 1-cos2x/sin2x please ...
- trigonometry (please double check this) - Solve the following trig equations. ...
- Math - Trig - Double Angles - Prove: sin2x / 1 - cos2x = cotx My Attempt: LS: = ...
- Math - Explain how do you find the period of Y = cos(6x) from your graph. what ...
- Physics (Calc Based) - I understand how to solve this problem ,however cannot ...

More Related Questions