Posted by **Julie** on Friday, July 22, 2011 at 9:00pm.

A stone is dropped from the edge of a roof, and hits the ground with a velocity of -145 feet per second. How high (in feet) is the roof

- Calculus -
**Damon**, Friday, July 22, 2011 at 9:03pm
Ke = (1/2) m v^2 = (1/2) m (145^2)

pe = m g h where g = 32.2 in ft/seconds units

32.2 m h = (1/2) m (145^2)

h = 326 feet

- Calculus -
**bobpursley**, Friday, July 22, 2011 at 9:03pm
vf^2=2gh

solve for h, in feet

g= 32ft/s^2

- Calculus -
**Anonymous**, Monday, March 12, 2012 at 1:52am
Hey Bob, I was wondering why gravity is 32m/s^2 instead of 9.8m/s^2. Can you explain why this is?

- Calculus -
**Anonymous**, Thursday, June 7, 2012 at 3:23am
Check the units m/s^2 and ft/s^2

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