algebra
posted by babs on .
solve by elimination x+6y=12
x+7y=1

x + 6y = 12  Equation 1
x + 7y = 1  Equation 2
13y = 13
y = 13/13
y = 1
sub y = 1 in equation 1 we get:
x + 6y = 12
x + 6(1)= 12
x + 6 = 12
x = 12  6
x = 6
Hence, x = 6 when y = 1