Homework Help: Fund. of Electronics

Posted by Brendon on Friday, July 22, 2011 at 7:22pm.

What is the peak to peak Voltage across a 10 kilo ohm resistor that dissipates 50 mW?

Fund. of Electronics - drwls, Friday, July 22, 2011 at 8:45pm
The rms voltage Vrms satisfies the equation

P = 50*10^-3 W = Vrms^2/R = V^2/50*10^3 ohms

Vrms^2 = 50^2
Vrms = 50 V

The peak to peak voltage is higher by a factor of sqrt2

V(p-p) = 70.7 V

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