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Posted by on Friday, July 22, 2011 at 9:25am.

find the eqt. of tangent to the curve y=-x^2+2x-10 @ the point where the curve cuts the y-axis.[ans:y=2x-10]
how do i do this because they didn't give me the point...?

  • math - , Friday, July 22, 2011 at 9:58am

    Yes, they did
    It said, "where the curve cuts the y-axis", that is when x = 0
    when x=0, y = -0 + 0 - 10 = -10
    so your point is (0,-10)

    drwls answered this for you already, did you not read it?

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