Posted by **rob** on Friday, July 22, 2011 at 9:25am.

find the eqt. of tangent to the curve y=-x^2+2x-10 @ the point where the curve cuts the y-axis.[ans:y=2x-10]

how do i do this because they didnt give me the point...?

- math -
**Reiny**, Friday, July 22, 2011 at 9:58am
Yes, they did

It said, "where the curve cuts the y-axis", that is when x = 0

when x=0, y = -0 + 0 - 10 = -10

so your point is (0,-10)

drwls answered this for you already, did you not read it?

http://www.jiskha.com/display.cgi?id=1311337279

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