Posted by **fanny** on Friday, July 22, 2011 at 8:21am.

find the eqt. of tangent to the curve y=-x^2+2x-10.[ans:y=2x-10]

but my ans is y=-9. if im wrong could you show the calculation.

- math -
**drwls**, Friday, July 22, 2011 at 8:37am
At what point along the curve is the tangent contact made?

Based upon the answer, it is where dy/dx = 2

dy/dx = -2x + 2 = 2, so x = 0 at the point of contact. That requires y = -10 at that point.

So y = 2x - 10 is the answer IF you are talking about the line tangent to the curve at x = 0.

You omitted an important part of the problem statement.

- math -
**rob**, Friday, July 22, 2011 at 9:05am
in the question it say: at the point where the curve cuts the y-axis

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