What volume of 14 N H2SO4 is needed to make 250 ml of 3.2 N H2SO4 solution?

mL1 x N1 = mL2 x N2

To calculate the volume of 14 N H2SO4 needed to make 250 ml of 3.2 N H2SO4 solution, we can use the formula:

M1V1 = M2V2

where:
M1 = initial concentration of H2SO4 (in this case, 14 N)
V1 = volume of initial solution (what we're trying to find)
M2 = final concentration of H2SO4 (in this case, 3.2 N)
V2 = final volume of solution (in this case, 250 ml)

Rearranging the formula to solve for V1, we get:

V1 = (M2 * V2) / M1

Plugging in the values:
M1 = 14 N
V2 = 250 ml
M2 = 3.2 N

V1 = (3.2 N * 250 ml) / 14 N

V1 = 57.14 ml

Therefore, you would need approximately 57.14 ml of 14 N H2SO4 to make 250 ml of 3.2 N H2SO4 solution.

To find the volume of 14 N H2SO4 needed to make 250 ml of a 3.2 N H2SO4 solution, we can use the formula:

(C1)(V1) = (C2)(V2)

where C1 is the concentration of the initial solution, V1 is the volume of the initial solution, C2 is the concentration of the final solution, and V2 is the volume of the final solution.

In this case, C1 is 14 N, V1 is unknown, C2 is 3.2 N, and V2 is 250 ml.

Rearranging the formula, we can solve for V1:

V1 = (C2)(V2) / C1
= (3.2 N)(250 ml) / 14 N
≈ 57.14 ml

Therefore, approximately 57.14 ml of 14 N H2SO4 is needed to make 250 ml of 3.2 N H2SO4 solution.