Tuesday

July 29, 2014

July 29, 2014

Posted by **Brit** on Thursday, July 21, 2011 at 7:22pm.

By the Mean Value Theorem, we know there exists at least one c in the open interval (–2,2) such that f(c) is equal to this mean slope.

For this problem, there are two values of c that work. The smaller one is_____ and the larger one is ______?

- CALCULUS! -
**Anonymous**, Thursday, July 21, 2011 at 7:40pmf(-2)=-32+4=-28

f(2)=32-4=28

f'(c)=(28-(-28))/(2-(-2))=14

f'(c)=12c^2-2=14

c^2=16/12=4/3

c=+-2/sqrt(3)

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