Friday

December 19, 2014

December 19, 2014

Posted by **Brit** on Thursday, July 21, 2011 at 7:22pm.

By the Mean Value Theorem, we know there exists at least one c in the open interval (–2,2) such that f(c) is equal to this mean slope.

For this problem, there are two values of c that work. The smaller one is_____ and the larger one is ______?

- CALCULUS! -
**Anonymous**, Thursday, July 21, 2011 at 7:40pmf(-2)=-32+4=-28

f(2)=32-4=28

f'(c)=(28-(-28))/(2-(-2))=14

f'(c)=12c^2-2=14

c^2=16/12=4/3

c=+-2/sqrt(3)

**Answer this Question**

**Related Questions**

calculus - Consider the function f(x)=–3x3–1x2+1x+1Find the average slope of ...

calculus - Consider the function f(x)=4sqrtx+5 on the interval [4,5]. Find the ...

Calculus Please help! - Consider the function f(x)=4sqrt(x)+4 on the interval [2...

calculus - Consider the function f(x)=6sqrt(x)+1 on the interval [3,5] . Find ...

math - Consider the function f(x)=2sqrtx+4 on the interval [2,8]. Find the ...

calculus - Consider the function f(x)=3x^2 – 5x on the interval [-4,4]. Find the...

Calc, Mean Value Theorem - Consider the function : 3x^3 - 2x^2 - 4x + 1 Find the...

calc - consider the function f(x)=x^3 - x^2 - 3x -2. find the average slope of ...

math - Consider the function f(x)=–2x^3–3x^2+2x–2 Find the average slope of this...

Calculus - Find the average or mean slope of 2x^3 - 6x^2 - 90x +3 on the ...