posted by Kyle on .
An ant walks on a piece of graph paper straight along the x axis a distance of 10.0 cm in 2.00 s. It then turns left 30.0 degrees and walks in a straight line another 10.0 cm in 1.90 s. Finally, it turns another 70.0 degrees to the left and walks another 10.0 cm in 1.40 s.
A. Determine the x component of the ant's average velocity.
*** I don't know how to find the x or y coordinates for this problem!!***
B. Determine the y component of the ant's average velocity.
C. Determine the magnitude of ant's average velocity.
D. Determine the direction of ant's average velocity.
I assume you have had some trignometry.
x component=10+10cos30 + 10cos(70+30)
go through that and make certain you understand it. I will be happy to check your y component.
I got the x-component to be: 10+8.66+3.42 which is 22.08.
But I also have to divide that by the total time that the ant traveled, right? So that time would be 5.3?
I got 4.166 when I divided it but the correct answer it supposed to be 3.19.
I really don't know how to get that answer. Could you please check my work please?
Well, the time is right, 5.3seconds.
The problem is, what is cosine100? It is negative right?