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July 31, 2014

July 31, 2014

Posted by **Ms.Ellis** on Thursday, July 21, 2011 at 8:49am.

(x-4x^3)^2

=(x-4x^3)(x-4x^3)=(x)(x)+(x)(-4x^3)+(-4x^3)(x)+(-4x^3)(4x^3)

= x^2-4x^4-4x^4-16x^6

=x^2-8x^4-16x^6

- Math -
**Reiny**, Thursday, July 21, 2011 at 9:43amYour answer is correct. You did nothing wrong.

- Math -
**Anonymous**, Thursday, July 21, 2011 at 10:08am-16x^2=>+16x^2

- check this again - Math -
**Reiny**, Thursday, July 21, 2011 at 10:35amshould have looked a bit more carefully

the last term should be + 16x^6

(in your second line: should have been

=(x-4x^3)(x-4x^3)=(x)(x)+(x)(-4x^3)+(-4x^3)(x)+(-4x^3)**(-4x^3)**

- Math -
**Ms.Ellis**, Thursday, July 21, 2011 at 2:27pmThanks Reiny, Thanks Anonymous I went over it and found the problem.

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