Posted by
**Krisha** on
.

RATE = ([ Na2S2O3]/time) = k [I-]a [BrO3-]b [HCl]c

1A) You mix together in the proper manner the following:

10.0 mL of .0100 M Potassium Iodide

10.0 mL of .00100 M Sodium thiosulfate

10.0 mL of water

10.0 mL of .0400 M Potassium Bromate

10.0 mL of .100 M HCl

The time to turn blue is... 84 sec

1B) You also mix together in the proper manner the following:

10.0 mL of .0100 M Potassium Iodide

10.0 mL of .00100 M Sodium thiosulfate

20.0 mL of .0400 M Potassium Bromate

10.0 mL of .100 M HCl

The time to turn blue is... 22 sec

Calculate

The Experimental value of exponent a..._______________ (a)

2) If the exponents a, b, and c have the values:

a = 0; b = 2; c = 1

CALCULATE:

Rate constant k for data in 1A...______________ (b)

3) You mix together in the proper manner the following VOLUMES:

0.0100 M Potassium iodide...8.3 mL

0.0010 M Sodium thiosulfate...8.3 mL

Distilled water...18.0 mL

0.0400 M Potassium Bromate...6.9 mL

0.100 M Hydrochloric acid...5.7 mL

Using the rate constant and rate equation from problem 2),

CALCULATE the time to turn blue...__________________ sec (c)

4) A plot of log Rate vs 1/T gives a best straight line which goes through....

1/T = 0.00300, log rate = -4.20

and 1/T = 0.00395, log rate = -6.00.

CALCULATE:

The Slope of the line..._____________ (d)

The Activation Energy (Ea) (Kj/mol)...________________(e)