Posted by **Aria** on Wednesday, July 20, 2011 at 7:26pm.

If the profit equation for the monthly sales of tile sets is P = -x^2 + 56x - 300, how do I find the number of tiles that yeilds the most profit.

x=number of tile sets. The amount of money for costs each month is set at $300.

I saw an answer as 28 tile sets would yeild the highest profit but I don't understand why that is the answer, if it is.

Could you help me? Thanks so much.

- Algebra -
**Damon**, Wednesday, July 20, 2011 at 8:24pm
x^2 -56 x = -p - 300

complete the square to find vertex of parabola

x^2 -56 x + 784 = -p +484

(x-28)^2 = - (p-484)

so

vertex (max of p) is at (28,484)

- Algebra -
**Aria**, Wednesday, July 20, 2011 at 9:12pm
Damon,

Why does this explain the highest yeild?

It sounds like what you did was on a graph and you found the highest points

- Algebra -
**Linda**, Monday, November 14, 2011 at 2:25pm
-4x^3 + 24x^2 – 24x + 4 by x^2 – 5x + 1

## Answer this Question

## Related Questions

- Algebra - I was wondering if I had number 2 correct; the only way to know the ...
- Algebra - Sorry, it didn't paste the first time, I was wondering if I got these ...
- ALGEBRA - The profit made from the sale of tiles is found by subtracting the ...
- ALGEBRA - I HAVE TO SOLVE THE FOLLOWING PROBLEMS FOR AN ALGEBRA ASSIGNMENT DUE ...
- Algebra - The costs of doing business for a company can be found by adding fixed...
- Algebra - The profit made from the sale of tiles is found by subtracting the ...
- Math - 1. In this problem, we analyze the profit found for sales of decorative ...
- algebra - Let cost = 600.00 fixed costs x = set of tiles $11.00 find the profit ...
- Algebra - 1.In this problem, we will analyze the profit found for sales of ...
- math - 1. In this problem, we analyze the profit found for sales of decorative ...