Tuesday

March 31, 2015

March 31, 2015

Posted by **susan** on Wednesday, July 20, 2011 at 9:30am.

can anyone explain why the 1 is zero & the 2 is infinity.

- math -
**Reiny**, Wednesday, July 20, 2011 at 1:20pmTry to get a "feel" for numbers.

look at 3/(y+4)

As the y+4 gets larger and larger, and since the top stays constant at 3, the quotient gets smaller and smaller.

e.g. let y = 1 000 000, (not even close to infinity)

the quotient is 3/(1000000 +4) = 0.000003

pretty close to zero, but we have a long way to go in making y ---> infinity

for the (7 - 6x^5)/(x+3) , x--->+infinity

pick a "large value of x" , say x = 1000

so you would get (7 - 6000 000 000 000 000)/1003

would you not agree that this is a huge negative number ? And our x is not even remotely "large".

You might even want to experiment with your calculator.

**Answer this Question**

**Related Questions**

Calc. Limits - Are these correct? lim x->0 (x)/(sqrt(x^2+4) - 2) I get 4/0...

calc - Are these correct? lim x->0 (x)/(sqrt(x^2+4) - 2) I get 4/0= +/- ...

Calc Please Help - Are these correct? lim x->0 (x)/(sqrt(x^2+4) - 2) I get 4/...

Math - 1. If -1/infinity = infinity or -infinity ? 2. If lim x->infinity^- = ...

Math - 1. If -1/infinity = infinity or -infinity ? 2. If lim x->infinity^- = ...

Calculus - Find the horizontal asymptote of f(x)=e^x - x lim x->infinity (e^x...

calculus - State which of the conditions are applicable to the graph of y = f(x...

calculus - interval of convergence - infinity of the summation n=0: ((n+2)/(10^n...

Pre-cal - Please determine the following limits if they exist. If the limit does...

Calculus - ratio test - infinity of the summation n=1: (e^n)/(n!) [using the ...