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April 18, 2014

April 18, 2014

Posted by **elli** on Wednesday, July 20, 2011 at 6:51am.

- math -
**Damon**, Wednesday, July 20, 2011 at 6:57amy = e^x * x^-.5

y' = e^x (-.5) x^-1.5 + x^-.5 e^x

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