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September 20, 2014

September 20, 2014

Posted by **shay** on Tuesday, July 19, 2011 at 11:08pm.

- algebra -
**Henry**, Wednesday, July 20, 2011 at 4:15pmArea = (2x+1)S = 2x^2 - 5x -3,

S = (2x^2 -5x -3) / (2x+1),

Factor the numerator and get:

S = (x-3)(2x+1) / (2x+1),

S = x - 3. = Expression for other side.

The AC Method was used for factoring:

A*C = 2 * (-3) = -6 = 1*(-6) = 2*(-3).

Select the pair of factors whose sum =

-5:

2x^2 + x-6x - 3 = 0,

Group the 4 terms into 2 factorable pairs:

(2x^2+x) + (-6x-3) = 0,

x(2x+1) - 3(2x+1) = 0,

(2x+1)(x-3) = 0,

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