Posted by shay on Tuesday, July 19, 2011 at 11:08pm.
Area = (2x+1)S = 2x^2 - 5x -3,
S = (2x^2 -5x -3) / (2x+1),
Factor the numerator and get:
S = (x-3)(2x+1) / (2x+1),
S = x - 3. = Expression for other side.
The AC Method was used for factoring:
A*C = 2 * (-3) = -6 = 1*(-6) = 2*(-3).
Select the pair of factors whose sum =
-5:
2x^2 + x-6x - 3 = 0,
Group the 4 terms into 2 factorable pairs:
(2x^2+x) + (-6x-3) = 0,
x(2x+1) - 3(2x+1) = 0,
(2x+1)(x-3) = 0,
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