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Q. How many megabytes of memory would be required to store an uncompressed 2-minute video file which is played at 24 frames per second, with a frame size of 320 × 240 pixels using a 24-bit per pixel colour model?

A. 320*240*24 = 1843200 bytes
since, 24*120 = 2880 sec

therefore, 2880*1843200 = 5308416000bytes
~ 5062.5 MB

  • statistics - ,

    =320*240*(24/8)[8 bits is equal to 1 byte]
    =320*240*3
    =230400 bytes
    since,
    24*120=2880 frames
    therefore, 2880*230400 bytes
    which is 663 MB ~ 633MB

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