given the linear equation y=7/6x+1, find the y-corrdinates of the points (-6,),(0,)and (6,). plot those points and graph the linear equation.
This question is practically the same as yours
http://www.jiskha.com/display.cgi?id=1310950767
For x= -6
y=(7/6)*(-6)+1= -7+1= -6
For x=0
y=(7/6)*0+1= 0+1=1
For x=6
y=(7/6)*(6)+1=7+1=8
For graph go on:
rechneronline.de/function-graphs
When page be open in blue rectangle type:
(7/6)*x+1
Then type:
Range x-axis from -10 to 10
Range y-axis from -10 to 10
and click option: Draw
To find the y-coordinates of the points (-6,), (0,), and (6,) on the linear equation y = 7/6x + 1, we simply substitute the x-values into the equation and solve for y.
1. For the point (-6,), substitute x = -6 into the equation:
y = 7/6(-6) + 1
y = -7/6 + 1
y = -7/6 + 6/6
y = -1/6
Therefore, the y-coordinate of the point (-6,) is -1/6.
2. For the point (0,), substitute x = 0 into the equation:
y = 7/6(0) + 1
y = 0 + 1
y = 1
Therefore, the y-coordinate of the point (0,) is 1.
3. For the point (6,), substitute x = 6 into the equation:
y = 7/6(6) + 1
y = 7/6 + 1
y = 7/6 + 6/6
y = 13/6
Therefore, the y-coordinate of the point (6,) is 13/6.
Next, plot these points (-6, -1/6), (0, 1), and (6, 13/6) on a Cartesian coordinate plane.
Finally, graph the linear equation y = 7/6x + 1 by connecting the three plotted points.