find the slope and y-intercept of the line y=-8/11x-5
for the equation
y = mx + b , m is the slope and b is the y-intercept
you have
y = (-8/11)x - 5
what do you think?
To find the slope and y-intercept of the line represented by the equation y = -8/11x - 5, we can compare it to the standard slope-intercept form: y = mx + b.
In this equation:
- The coefficient of x, -8/11, represents the slope (m) of the line.
- The constant term -5 is the y-intercept (b) which is the point where the line intersects the y-axis.
So, in this case:
Slope (m) = -8/11
Y-intercept (b) = -5
Therefore, the slope of the line is -8/11 and the y-intercept is -5.
To find the slope and y-intercept of a line in the standard form equation (y = mx + b), you can directly compare the equation with the standard form equation (y = mx + b).
In the given equation y = -8/11x - 5, the coefficient of x (-8/11) represents the slope (m), and the constant term (-5) represents the y-intercept (b).
Therefore, the slope of the line is -8/11, and the y-intercept is -5.