Posted by **victor** on Monday, July 18, 2011 at 11:16pm.

Pelicans tuck their wings and free-fall straight down when diving for fish. Suppose a pelican starts its dive from a height of 15.0 m and cannot change its path once committed.

If it takes a fish 0.25 s to perform evasive action, at what minimum height must it spot the pelican to escape? Assume the fish is at the surface of the water.

- physics -
**drwls**, Tuesday, July 19, 2011 at 2:36am
The fish must spot the pelican when it is 0.25 s (or more) from hitting the water.

The pelican takes

t = sqrt(2H/g) = 1.75 s to hit the water if it starts its dive at H = 15 m.

Its vertical drop 1.50 s after starting the dive is y = (1/2)g*(1.50)^2 = 11.03 m

It is 15 - 11.03 = 4.97 m above the water surface at that time,

## Answer this Question

## Related Questions

- physics - a pelican flying a horizontal path drops a fish from a height of 5.0m...
- physics - A pelican flying along a horizontal path drops a fish from a height of...
- physics - A pelican flying along a horizontal path drops a fish from a height of...
- physics - A pelican flying along a horizontal path drops a fish from a height of...
- physics - A pelican flying along a horizontal path drops a fish from a height of...
- physics - A pelican flying along a horizontal path drops a fish from a height of...
- physics - A pelican flying along a horizontal path drops a fish from a height of...
- Physics - A pelican flying along a horizontal path drops a fish from a height of...
- physics - A pelican flying along a horizontal path drops a fish from a height of...
- physics - A pelican flying along a horizontal path drops a fish from a height of...