Posted by josh on Monday, July 18, 2011 at 10:53pm.
It is 9.81 m/s^2, multiplied by an inverse square law term,
(6380/6580)^2,
to accounnt for the reduction with increased distance from the center of the earth.
g' = 9.81*0.940 = 9.22 m/s^2
Related Questions
Phys Science - Good afternoon tutors..I need help on a few problems.Im really ...
phys sci - the space shuttle orbits at an altitude of approximately 200 km ...
Physics help please - The space shuttle orbits at a distance of 335 km above the...
Math - Radius of earth 3,959 miles Space shuttle orbits 200 miles above earths ...
Math - Radius of earth 3,959 miles Space shuttle orbits 200 miles above earths ...
physics - . The space shuttle typically orbits 400 km above the earth's ...
space - What is the value of g for space-shuttle territory , about 200km above ...
Math 8th Grade Please help - The radius of Earth is 6,371 kilometers. A space ...
Physics - When the space shuttle (mass of the shuttle = 2 x10^6 kg) was at the ...
physics - The Earths radius is about 6380 km. The space shuttle is ...
For Further Reading