A transformation T : (x, y) (x + 3, y + 1).
The image of B(4, 1) under this transformation is
4+3 = 7
1+1 = 2
To find the image of point B(4, 1) under the transformation T : (x, y) → (x + 3, y + 1), we need to apply the transformation rules to the coordinates of point B.
For the x-coordinate:
x-coordinate of image = x-coordinate of B + 3
= 4 + 3
= 7
For the y-coordinate:
y-coordinate of image = y-coordinate of B + 1
= 1 + 1
= 2
Therefore, the image of point B(4, 1) under the transformation T is B'(7, 2).