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April 16, 2014

April 16, 2014

Posted by **sissy** on Monday, July 18, 2011 at 2:26pm.

- algebra -
**Reiny**, Monday, July 18, 2011 at 3:16pmSince we have a "half-life" situation I can use a base of 1/2

.977 = (1/2)^(t/2.52x10^5)

t/2.52x10^5 = ln.977/ln.5

t = 2.52x10^5(ln.97/ln.5) = 8459.22 years or 9000 years to the nearest thousand years

for an alternate solution see MathMate's

http://www.jiskha.com/display.cgi?id=1310960571

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