Homework Help: Physics

Posted by Edward on Monday, July 18, 2011 at 12:38am.

15kg block rests on a rough surface (u=.35) a 100N force to the left is applied to the block.
what is the magnitude and direction of the net force acting on the block?
How quickly will the block accelerate over the rough surface?

Physics - Henry, Monday, July 18, 2011 at 7:16pm
1. Fb = mg = 15kg * 9.8N/kg = 147N.

147N @ 0 deg.

Fp = 147sin(0) = 0 = Force parallel to plane(hor.).

Fv = 147cos(0) = 147N = Force perpendicular to plane.

Ff = u*Fv = 0.35 * 147 = 51.45N.

Fn = Fap - Fp - Ff,
Fn = 100 - 0 - 51.45 = 48.6N = Net force parallel to the hor plane.

Answer this Question

Related Questions

Physics - A 10 kg block is pushed across a rough surface by a 25N force the ...
Physics - A block of mass m = 2.00 kg rests on the left edge of a block of mass ...
Physics. - A block of mass 3m is placed on a frictionless horizontal surface, ...
Physics - A block of mass 3m is placed on a frictionless horizontal surface, and...
Physics - A block of mass 3m is placed on a frictionless horizontal surface, and...
physics - Two cubic blocks are in contact, resting on a frictionless horizontal...
Physics - Two cubic blocks are in contact, resting on a frictionless horizontal ...
Physics - A force of 50 N directed 30 degrees above the hoizontal is applied to ...
Physics - A block of mass M1=2.9 kg rests on top of a second block of mass2=5.5 ...
Physics - A block (weight= 10kg) is sitting on a surface with friction (...

For Further Reading

First Name:
School Subject:
Answer: