Posted by Starr on Sunday, July 17, 2011 at 7:06pm.
a. There are 4 aces and twelve face cards and 4 10s in a deck of 52 cards.
4/52(for aces)*16/51(for cards = 10 once an ace has been drawn)
For probability that all/both are found by multiplying the individual probabilities.
4/52 * 16/51 = ?
b. 16/52 * 15/51 = ?
c. What combinations of two cards will give you 16 or less? Figure combos for 16 = 6,10; 5,9; etc.
It might be easier to calculate for values greater than 16 and subtract from 1.
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