Posted by **pop** on Sunday, July 17, 2011 at 5:54pm.

A major-league catcher gloves a 92 mi/h pitch and brings it to rest in 0.15 m.

1-If the force exerted by the catcher is 803 N, what is the mass of the ball?

- phy -
**Damon**, Sunday, July 17, 2011 at 6:15pm
speed = 92 mi/hr * 1 hr/3600 s * 621 m/mi

= 15.9 m/s

average speed = 15.9/2 = 7.9 m/s

time to stop = distance/speed = .15/7.9 = .0189 second

force * time = change of momentum

803 * .0189 = m (15.9 - 0)

m = .955 kg

- conversion error -
**Damon**, Sunday, July 17, 2011 at 6:25pm
speed = 92 mi/hr * 1 hr/3600 s * 1610 m/mi

= 41.1 m/s

average speed = 41.1/2 = 20.6 m/s

time to stop = distance/speed = .15/20.6 = .0073 second

force * time = change of momentum

803 * .0073 = m (41.1 - 0)

m = .142 kg

- Help!! -
**Marie**, Wednesday, November 9, 2011 at 8:45pm
A catcher stops 92 mi/h pitch in his glove bring it to rest in 0.15 m. If the force exerted by the catcher is 803N, what is the mass of the ball?

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