Posted by Heat on Sunday, July 17, 2011 at 5:17pm.
Ice heat gain = coffee heat loss.
Assume all the ice melts.
500(g)*80(cal/g)= 500 (g)* 1(cal/gC)*(80-T)
where T is the final temperature.
T = 0
Each gram of melting ice gains absorbs 80 cal of heat while melting. That is enough to lower the temperature of 80 g of water by 1 degree.
In this case, all of the ice melts and the water temperature reaches 0 C.
It the computed T had been less than 0, you would have had to assume that all of the ice did not melt, and do the problem differently.
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