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March 1, 2015

March 1, 2015

Posted by **mary** on Sunday, July 17, 2011 at 4:36pm.

p $25 potted plants and s $20 shrubs total $300

Graph the equation and use the graph to determine three different combinations of potted plants and shrubs that total $300.

- math -
**mary**, Sunday, July 17, 2011 at 5:14pmcan someone pleae help me???

- math -
**Anonymous**, Monday, July 18, 2011 at 3:30am25*x+20*y=300

x=numbers of potted plants

y=numbers of shrubs

You can divide both sides by 5, giving the following:

(25*x)/5 + (20*y)/5 = 300/5

5p + 4s = 60

You could set it up as follows; given a "p" value, you can find "s":

4s = 60 - 5p Divide both sides with 4

(4s)/4 = (60/4) - (5p/4)

s = 15 - 5p/4

To plot it, you might think of "p" and "s" as "x" and "y".

p can be 0 or number divisible with 4

Here are possible solutions:

p = 0

s = 15 - 5p/4

s = 15 - 5*0/4 = 15 -0 = 15

p=0

s = 15

0*20$ + 15*20$ = 0+300$ = 300$

p = 4

s = 15 - 5p/4

s = 15 - 5*4/4 = 15 - 20/4 = 15 -5 = 10

p=4

s=10

4*25$ + 10*20$ = 100$ + 200$ = 300$

p = 8

s = 15 - 5p/4

s = 15 - 5*8/4 = 15 - 40/4 = 15 -10 = 5

p=8

s = 5

8*25$ + 5*20$ = 200 + 100$ = 300$

p = 12

s = 15 - 5p/4

s = 15 - 5*12/4 = 15 - 60/4 = 15 -15 = 0

p=12

s=0

12*25$ + 0*20$ = 300$ + 0 = 300$

For graph go to:

wolframalpha dot com

and type:

plot (15-5p/4) (p=-5 to 15)

then click option =

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