Translate to an equation:

p $25 potted plants and s $20 shrubs total $300

Graph the equation and use the graph to determine three different combinations of potted plants and shrubs that total $300.

can someone pleae help me???

25*x+20*y=300

x=numbers of potted plants

y=numbers of shrubs

You can divide both sides by 5, giving the following:

(25*x)/5 + (20*y)/5 = 300/5

5p + 4s = 60

You could set it up as follows; given a "p" value, you can find "s":

4s = 60 - 5p Divide both sides with 4

(4s)/4 = (60/4) - (5p/4)

s = 15 - 5p/4

To plot it, you might think of "p" and "s" as "x" and "y".

p can be 0 or number divisible with 4

Here are possible solutions:

p = 0

s = 15 - 5p/4

s = 15 - 5*0/4 = 15 -0 = 15

p=0

s = 15

0*20$ + 15*20$ = 0+300$ = 300$

p = 4

s = 15 - 5p/4

s = 15 - 5*4/4 = 15 - 20/4 = 15 -5 = 10

p=4

s=10

4*25$ + 10*20$ = 100$ + 200$ = 300$

p = 8

s = 15 - 5p/4

s = 15 - 5*8/4 = 15 - 40/4 = 15 -10 = 5

p=8

s = 5

8*25$ + 5*20$ = 200 + 100$ = 300$

p = 12

s = 15 - 5p/4

s = 15 - 5*12/4 = 15 - 60/4 = 15 -15 = 0

p=12

s=0

12*25$ + 0*20$ = 300$ + 0 = 300$

For graph go to:

wolframalpha dot com

and type:

plot (15-5p/4) (p=-5 to 15)

then click option =

To translate the given information into an equation, let's assign variables to represent the unknown quantities. Let p represent the number of $25 potted plants and s represent the number of $20 shrubs.

Given that there are p $25 potted plants and s $20 shrubs, and the total cost is $300, we can represent the equation as follows:

25p + 20s = 300

Now, let's graph this equation to determine three different combinations of potted plants and shrubs that total $300.

To graph the equation, we will use a coordinate plane with the number of potted plants (p) on the x-axis and the number of shrubs (s) on the y-axis.

1. Choose three different values for p and substitute them into the equation to find the corresponding values of s:

Let p = 0: 25(0) + 20s = 300
0 + 20s = 300
20s = 300
s = 300/20
s = 15

The first combination is (0, 15), meaning there are 0 potted plants and 15 shrubs that cost a total of $300.

2. Let p = 5:
25(5) + 20s = 300
125 + 20s = 300
20s = 300 - 125
20s = 175
s = 175/20
s ≈ 8.75

The second combination is (5, 8.75), meaning there are 5 potted plants and approximately 8.75 shrubs that cost a total of $300.

3. Let p = 10:
25(10) + 20s = 300
250 + 20s = 300
20s = 300 - 250
20s = 50
s = 50/20
s = 2.5

The third combination is (10, 2.5), meaning there are 10 potted plants and 2.5 shrubs that cost a total of $300.

Plotting these three combinations on the graph will help visualize the equation and the combinations that satisfy it.