Tuesday

January 27, 2015

January 27, 2015

Posted by **Anonymous** on Sunday, July 17, 2011 at 1:17pm.

- math -
**Reiny**, Sunday, July 17, 2011 at 1:44pmyou could use

amount = initial(1/2)^(t/5730)

.88 = 1(1/2)^(t/5730)

t/5730ln.5 = ln .88

t = 5730ln.88/ln.5 = 1056.75 yrs.

or

let amount = initial (e^(kt))

when t = 5730 amount = .5

.5 = e^(5730k)

k = ln.5/5730 = -0.000120968

.88 = e^(-.000120968t)

t = ln.88/-.000120968

= 1056.75

**Answer this Question**

**Related Questions**

math - An artifact was found and tested for its carbon-14 content. If 79% of the...

math - An artifact was found and tested for its carbon-14 content. If 76% of the...

math - An artifact was found and tested for its carbon-14 content. If 83% of the...

math - An artifact was found and tested for its carbon-14 content. If 83% of the...

math - An artifact was found and tested for its carbon-14 content. If 76% of the...

math - An artifact was found and tested for its carbon-14 content. If 81% of the...

Math - An artifact was found and tested for its carbon-14 content. If 88% of the...

College Math - An artifact was found and tested for its carbon-14 content. If 88...

alegbra - An artifact was found and tested for its carbon-14 content. If 75% of ...

Alegbra - An artifact was found and tested for its carbon-14 content. If 75% of ...