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November 29, 2014

November 29, 2014

Posted by **Anonymous** on Sunday, July 17, 2011 at 1:17pm.

- math -
**Reiny**, Sunday, July 17, 2011 at 1:44pmyou could use

amount = initial(1/2)^(t/5730)

.88 = 1(1/2)^(t/5730)

t/5730ln.5 = ln .88

t = 5730ln.88/ln.5 = 1056.75 yrs.

or

let amount = initial (e^(kt))

when t = 5730 amount = .5

.5 = e^(5730k)

k = ln.5/5730 = -0.000120968

.88 = e^(-.000120968t)

t = ln.88/-.000120968

= 1056.75

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