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December 20, 2014

December 20, 2014

Posted by **Josh** on Sunday, July 17, 2011 at 1:20am.

cot2 beta/1+csc beta=1-sin beta/sin beta.

- calculus -
**Reiny**, Sunday, July 17, 2011 at 8:13amdid you mean

cot^2 ß/(1+cscß) = (1-sinß)/sinß ?

from the identity

sin^ Ø + cos^2 Ø = 1

if we divide each term by sin^2Ø ......

1 + cot^2 Ø = csc^2 Ø ----> cot^2 Ø = csc^2Ø - 1

LS

= (csc^2 ß - 1)/(1 + csc ß)

= (cscß + 1)(cscß - 1)/(1 + cscß)

= cscß - 1

= 1/sinß - sinß/sinß

= (1 - sinß)/sinß

= RS

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