Posted by Josh on .
Verify the identity
cot2 beta/1+csc beta=1sin beta/sin beta.

calculus 
Reiny,
did you mean
cot^2 ß/(1+cscß) = (1sinß)/sinß ?
from the identity
sin^ Ø + cos^2 Ø = 1
if we divide each term by sin^2Ø ......
1 + cot^2 Ø = csc^2 Ø > cot^2 Ø = csc^2Ø  1
LS
= (csc^2 ß  1)/(1 + csc ß)
= (cscß + 1)(cscß  1)/(1 + cscß)
= cscß  1
= 1/sinß  sinß/sinß
= (1  sinß)/sinß
= RS