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September 1, 2014

September 1, 2014

Posted by **Ms.Ellis** on Friday, July 15, 2011 at 11:54pm.

4x^4y-8x^6y^2+12x^8y^6

_______________________

4x^4y

- Math -
**Henry**, Saturday, July 16, 2011 at 3:20pmWhen dividing fractions, we divide the

coefficients and subtract the exponents in the denominator from those

in the numerator.

4X^4y/4X^4y - 8X^6y^2/4X^4y + 12X^8y^6/4X^4y =

1 - 2X^(6y^2-4y) + 3X^(8y^6-4y)

Factor the exponents of each term:

1 - 2X^2y(3y-2) + 3X^4y(2y^5-1).

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