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December 17, 2014

December 17, 2014

Posted by **kyle** on Friday, July 15, 2011 at 11:05pm.

5 logb m -6/5 logb n +1/3 logb j - 2 logb k

- algebra 2 -
**Reiny**, Friday, July 15, 2011 at 11:10pm5 logb m -6/5 logb n +1/3 logb j - 2 logb k

= logb m^5 - logb n^(6/5) + logb j^(1/3) - logb k^2

= logb (m^4 j^(1/3)/(n^(6/5) k^2) )

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