Posted by SANDY on .
FIND A PERIMETER OF A TRIANGLE WHERE ONE SIDE IS 2 INCHES, ONE SIDE IS 6 INCHES, ANOTHER SIDE IS 10 INCHES???
2 + 6 + 10 = ?
MATH : pitfall -
Unfortunately the triangle does not exist.
Any properly formed triangle has to have any two of its sides greater than or equal to the third.
In this example, the sides 2 and 6 will never meet to form a triangle, since the base is 10 inches.
Mathematically, this can be expressed as:
All three conditions must be satisfied for the triangle to "exist".