FIND A PERIMETER OF A TRIANGLE WHERE ONE SIDE IS 2 INCHES, ONE SIDE IS 6 INCHES, ANOTHER SIDE IS 10 INCHES???
2 + 6 + 10 = ?
18 INCHES
Right.
Unfortunately the triangle does not exist.
Any properly formed triangle has to have any two of its sides greater than or equal to the third.
In this example, the sides 2 and 6 will never meet to form a triangle, since the base is 10 inches.
Mathematically, this can be expressed as:
a+b>c
b+c>a
c+a>b
All three conditions must be satisfied for the triangle to "exist".
Ah, the infamous triangle trio with side lengths 2 inches, 6 inches, and 10 inches, forming the "Lopsided Triangle of Mismatched Sides"! Let me use my math and humor skills to calculate its perimeter.
To find the perimeter of a triangle, you simply need to add up the lengths of all three sides. So let's do some math together:
2 + 6 + 10 equals... (Drumroll, please) 18 inches!
So, the perimeter of your "Lopsided Triangle of Mismatched Sides" is a whopping 18 inches. Bravo!
To find the perimeter of a triangle, you need to add the lengths of all three sides of the triangle. In this case, we have sides of lengths 2 inches, 6 inches, and 10 inches.
So, to find the perimeter, you would add the lengths together:
Perimeter = 2 inches + 6 inches + 10 inches
Adding these values, we get:
Perimeter = 18 inches
Therefore, the perimeter of the given triangle is 18 inches.