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Posted by on Friday, July 15, 2011 at 10:07am.

An automobile travelling with a speed of 60km/hr, can apply brake to stop within a distance
of 20m. If the car is going twice as fast then calculate the stopping distance and stopping time?
(b) Given R1 = 5.0 ± 0.2 and R2 = 10.0 ± 0.1. calculate the total resistance in parallel with possible
% error?

  • Physics - , Friday, July 15, 2011 at 9:56pm

    a. The stopping distance is proportional to the square of the initial velocity:

    Ds = 2^2 * 20m = 80m = Stopping distance.

    The stopping time is proportional to the initial velocity:

    Vo = 60000m/h * (1h/3600s) = 16.67m/s.

    a = (Vf^2-Vo^2) / 2d,
    a = (0-(16.67)^2 / 40 = 6.94m/s.

    Ts = (vF-2Vo) / A,
    tS = (0 - 33.33) / -6.94 = 4.80s.

    b. Do you mean +-0.2% and +-0.1%?

  • Physics - , Tuesday, April 19, 2016 at 12:30pm

    32

  • Physics - , Wednesday, September 21, 2016 at 10:18am

    1346-

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