What volume of 0.25M solution can be made from5.0 gof KCl?
5.0 g KCl = how many moles?
moles = grams/molar mass.
Then M = moles/L. YOu know M and you know moles, solve for L.
To determine the volume of a 0.25M solution that can be made from 5.0 grams of KCl, we need to use the formula:
Molarity (M) = moles of solute / volume of solution (L)
First, we need to calculate the number of moles of KCl using its molecular weight. The molecular weight of KCl is the sum of the atomic weights of potassium (K) and chlorine (Cl). The atomic weight of potassium is 39.1 g/mol, and chlorine is 35.45 g/mol. Therefore, the molecular weight of KCl is:
Molecular weight (KCl) = 39.1 g/mol + 35.45 g/mol = 74.55 g/mol
Now, we can calculate the number of moles of KCl:
moles of KCl = mass (g) / molecular weight (KCl)
= 5.0 g / 74.55 g/mol
= 0.067 moles
Next, we can rearrange the formula to solve for the volume of the solution:
volume of solution (L) = moles of solute / Molarity
Now, we substitute the values we have:
volume of solution (L) = 0.067 moles / 0.25 mol/L
= 0.268 L
Therefore, the volume of a 0.25M KCl solution that can be made from 5.0 grams of KCl is 0.268 liters.