A seismic wave has a velocity of 5000 m/s and a frequency of 4Hz. wht is the wavelength of this wave? if this was a light wave traveling in a vacuum with the same wavelength, what would be its period?
frequency*wavelength=speedofPropagation
memorize that equation. It is called the wave equation.
Period = 1/frequency
To find the wavelength of a wave, we can use the formula:
wavelength = velocity / frequency
Given that the velocity of the seismic wave is 5000 m/s and the frequency is 4 Hz, we can substitute these values into the formula:
wavelength = 5000 m/s / 4 Hz
Simplifying, we get:
wavelength = 1250 m
Therefore, the wavelength of the seismic wave is 1250 meters.
Now, if this were a light wave traveling in a vacuum with the same wavelength, we can use the formula:
period = 1 / frequency
Since the frequency remains the same (4 Hz), we can calculate the period as follows:
period = 1 / 4 Hz
Simplifying, we get:
period = 0.25 s
Therefore, the period of the light wave with the same wavelength in a vacuum would be 0.25 seconds.