A seismic wave has a velocity of 5000 m/s and a frequency of 4Hz. wht is the wavelength of this wave? if this was a light wave traveling in a vacuum with the same wavelength, what would be its period?

frequency*wavelength=speedofPropagation

memorize that equation. It is called the wave equation.

Period = 1/frequency

To find the wavelength of a wave, we can use the formula:

wavelength = velocity / frequency

Given that the velocity of the seismic wave is 5000 m/s and the frequency is 4 Hz, we can substitute these values into the formula:

wavelength = 5000 m/s / 4 Hz

Simplifying, we get:

wavelength = 1250 m

Therefore, the wavelength of the seismic wave is 1250 meters.

Now, if this were a light wave traveling in a vacuum with the same wavelength, we can use the formula:

period = 1 / frequency

Since the frequency remains the same (4 Hz), we can calculate the period as follows:

period = 1 / 4 Hz

Simplifying, we get:

period = 0.25 s

Therefore, the period of the light wave with the same wavelength in a vacuum would be 0.25 seconds.