Friday

August 22, 2014

August 22, 2014

Posted by **Anonymous** on Thursday, July 14, 2011 at 7:11pm.

part 1: let U= 1/x and du= ?

-> using u=1/x, we can write h(x)= integral from (1, 1/x) arctan (2t)dt as h(u)= integral from (1,u) arctan(2t)dt and h'(u)= arctan (2)

Part 2: By the chain Rule, for functions h(u) and u(x), we have:

-> dh/dx= ______ du/dx

**Related Questions**

calculus - h(x)= integral from (1, 1/x) arctan(2t)dt part 1: let U= 1/x and du...

calc - also: integral of tan^(-1)y dy how is integration of parts used in that? ...

Calculus - integral -oo, oo [(2x)/(x^2+1)^2] dx (a) state why the integral is ...

calculus - Let f be a function defined by f(x)= arctan x/2 + arctan x. the value...

Integral Calculus - Trying to find ∫x*arctan(x)dx, but I can't figure out ...

Calc - Evaluate the integral (3x+4)/[(x^2+4)(3-x)]dx a. (1/2)ln(x^2+4) + ln|3-x...

precal - The values of x that are solutions to the equation cos^(2)x=sin2x in ...

calculus - Now we prove Machin's formula using the tangent addition formula: tan...

calculus - what is the integral of x^(2)arctan(6x) dx?

Calculus - How do you solve the integral from 0 to 1 of x arctan x dx?