How many moles of methane are produced when 8206 moles of carbon dioxide gas react with excess hydrogen gas?
Here is a step by step procedure for working stoichiometry problems. Just follow the steps. Print this out and keep it for reference. It will solve 99.9% of this kind of problem.
Here is a step by step procedure for working stoichiometry problems. Just follow the steps. Print this out and keep it for reference. It will solve 99.9% of this kind of problem.
oops. forgot to leave the link.
http://www.jiskha.com/science/chemistry/stoichiometry.html
To determine the number of moles of methane produced when 8206 moles of carbon dioxide gas react with excess hydrogen gas, we need to first write and balance the chemical equation for the reaction.
The balanced chemical equation for the reaction between carbon dioxide and hydrogen gas to produce methane is:
CO2 + 4H2 → CH4 + 2H2O
From the balanced equation, we can see that 1 mole of carbon dioxide (CO2) reacts with 4 moles of hydrogen gas (H2) to produce 1 mole of methane (CH4) and 2 moles of water (H2O).
Given that we have 8206 moles of carbon dioxide, we can use the stoichiometry of the balanced equation to calculate the number of moles of methane produced.
Using the mole ratio between CO2 and CH4 (1:1), we find that the number of moles of CH4 is also 8206.
Therefore, 8206 moles of methane are produced when 8206 moles of carbon dioxide gas react with excess hydrogen gas.