Posted by **Ann** on Thursday, July 14, 2011 at 4:22pm.

a train leaves a station and travels north at 85 km/hr. Four hours later, a second train leaves on a parrallel track and travels north at 125km/hr. How far from the station will they meet?

- Algembra -
**Henry**, Friday, July 15, 2011 at 5:34pm
Train #1 = t hrs.

Train #2 = (t-4)hrs.

When train #2 catches up, they would have traveled the same distance:

d1 = d2.

85t = 125(t-4),

85t = 125t - 500,

125t - 85t = 500,

40t = 500,

t = 12.5 hrs.

d = Vt = 85 * 12.5 = 1062.5km.

## Answer This Question

## Related Questions

- Math - A train leaves a station and travels north at a speed of 45mph. Four ...
- algebra - A train leaves a station and travels north at a speed if 50 mph. Five ...
- math - A train leaves a station and travels north at a speed of 105 mph. Two ...
- Algebra - A train leaves Danville Junction and travels north at a speed of 75 km...
- Mathematics - A train leaves station x and travels east at 30 kph. Two hours ...
- pre algebra - train A leaves a station at 1:15 PM,traveling 60 mph.Train B ...
- Algebra 2 - at 2 pm a freight train leaves a station and travels at 42 km/h. at ...
- college algebra - A freight rain leaves a station and travels north at a ...
- Algebra 2 (Distance Problem) - A train leaves Union Station for Central Station...
- Math - Train A and train B leave station going in opposite directions. Train B ...

More Related Questions