When NaCl dissolves in water it breaks up in sodium ions (Na+)and chloride ions(cl).500 ml of a 1M solution of NaCl contains how many (NA+) ions

What is 1/2 Avagradros Number?

is it 3*10.23square

To calculate the number of sodium (Na+) ions in 500 ml of a 1M solution of NaCl, you need to consider the relationship between molarity, volume, and the number of ions.

1M (1 mole per liter) means that there is 1 mole of NaCl dissolved in 1 liter of the solution. Therefore, in 500 ml (0.5 liters) of the solution, you have 0.5 moles of NaCl.

Since 1 mole of NaCl dissociates into 1 mole of Na+ ions and 1 mole of Cl- ions upon dissolving, you have the same number of sodium (Na+) ions as the number of moles of NaCl.

To convert moles of NaCl to the number of (Na+) ions, you need to multiply the number of moles by Avogadro's number (6.022 × 10^23 ions per mole). So, the calculation would be:

Number of (Na+) ions = Moles of NaCl × Avogadro's number

Using the given values:

Number of (Na+) ions = 0.5 moles × 6.022 × 10^23 ions/mol

Now you can calculate the answer by multiplying the moles of NaCl by Avogadro's number:

Number of (Na+) ions = 0.5 × 6.022 × 10^23 ions

Therefore, 500 ml of a 1M solution of NaCl contains approximately 3.011 × 10^23 sodium (Na+) ions.