Posted by **Katie ** on Wednesday, July 13, 2011 at 7:45pm.

intersect x^2+y^2=36-8x^2-8y^2

- Calc 3 -
**Reiny**, Wednesday, July 13, 2011 at 9:48pm
with .... ?

- Calc 3 -
**Anonymous**, Thursday, July 14, 2011 at 1:58am
x^2+y^2=36-8x^2-8y^2

x^2+8x^2+y^2+8y^2=36

9x^2+9y^2=36 Divide both sides with 9

x^2+y^2=4

That is circle.

x^2+y^2=R^2

Coordinates of center: 0,0

Radius: R=2

Intersect:

For x=0 y^2=4, y=sqrt(4)= +or- 2

For y=0 x^2=4, x=sqrt(4)= +or- 2

## Answer this Question

## Related Questions

- finite math - Given n(A')=23, n(B')=16, and n((A [intersect] B) U (AUB)'))= 24, ...
- Pre-calc - The plane y + 4z = 15 intersect which axes?
- math - Use the intersect command on a graphing utility to solve the following ...
- Precalculus - I know I posted this question already ,but I posted the wrong one...
- Calc. - Use normal vectors to determine the intersection, if any, for each of ...
- Calc. - Use normal vectors to determine the intersection, if any, for each of ...
- calc - find the area of the region bounded by y=4x, y=x^3, x=0 and x=2 Check ...
- Calc - Find the areas of the regions bounded by the lines and curves by ...
- Calc - Suppose Y1 is a function of x which dy1/dx=3y1. Suppose y2 is a function ...
- calculus - 5. Consider the circle x2 + y2 = 16 and the parabola y2 = 8x. They ...

More Related Questions