Calc 3
posted by
Katie
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intersect x^2+y^2=368x^28y^2

Calc 3 
Reiny
with .... ?

Calc 3 
Anonymous
x^2+y^2=368x^28y^2
x^2+8x^2+y^2+8y^2=36
9x^2+9y^2=36 Divide both sides with 9
x^2+y^2=4
That is circle.
x^2+y^2=R^2
Coordinates of center: 0,0
Radius: R=2
Intersect:
For x=0 y^2=4, y=sqrt(4)= +or 2
For y=0 x^2=4, x=sqrt(4)= +or 2