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January 28, 2015

January 28, 2015

Posted by **Jen** on Wednesday, July 13, 2011 at 6:08pm.

- Math-geometry -
**MathMate**, Wednesday, July 13, 2011 at 6:25pmthe truth table for bi-conditional <-> is

it is true when both p & q are true, or both are false.

p q (p^q) <-> ~p

T T T T T**F**F

T F T F F**F**T

F T F F T**F**F

F F F F F**F**T

Since in all cases, the proposition is false, it is a contradiction.

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