posted by Anonymous on .
How much heat is absorbed by a persons hand if 100 grams of steam at 100°C is first converted to liquid water at 100°C and then cooled to normal body temperature?
q1 = heat removed to condense steam at 100 to liquid at 100 C.
q1 = mass x heat vaporization
q2 = heat removed to cool from liquid water at 100 C to body temperature of 37 C.
q2 = mass water x specific heat water x (Tfinal-Tinitial). Tf = 37, Ti = 100.
Total heat absorbed by hand is q1 + q2.