Posted by John on Wednesday, July 13, 2011 at 2:12pm.
Find the vertex of the parabola associated with the quadratic function.
f(x)= 1/7x^2  2/11x + 1/121
(h,k)= What is the vertex of this quadratic function?

Math: Parabola, Vertex  Max, Wednesday, July 13, 2011 at 2:51pm
Hint: the xcoordinate of the vertex of a parabola y = ax^2 + bx + c is b/2a.

Math: Parabola, Vertex  Henry, Thursday, July 14, 2011 at 7:48pm
F(x) = x^2/7  2x/11 + 1/121,
h = b/2a = (2/11) / (2/7) = 7/11.
k = (7/11)^2/7 2(7/11)/11 + 1/121,
k = (49/121*1/7 + 14/11/11 + 1/121,
k = 7/121 +14/121 + 1/121 = 8/121.
V(h,k) = V(7/11,8/121).

Math: Parabola, Vertex  Cordarrell, Wednesday, March 30, 2016 at 11:51am
y^2+4y+2x=0
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