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January 29, 2015

January 29, 2015

Posted by **John** on Wednesday, July 13, 2011 at 2:12pm.

f(x)= -1/7x^2 - 2/11x + 1/121

(h,k)= What is the vertex of this quadratic function?

- Math: Parabola, Vertex -
**Max**, Wednesday, July 13, 2011 at 2:51pmHint: the x-coordinate of the vertex of a parabola y = ax^2 + bx + c is -b/2a.

- Math: Parabola, Vertex -
**Henry**, Thursday, July 14, 2011 at 7:48pmF(x) = -x^2/7 - 2x/11 + 1/121,

h = -b/2a = (2/11) / (-2/7) = -7/11.

k = -(-7/11)^2/7 -2(-7/11)/11 + 1/121,

k = -(49/121*1/7 + 14/11/11 + 1/121,

k = -7/121 +14/121 + 1/121 = 8/121.

V(h,k) = V(-7/11,8/121).

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