Posted by **elizabeth6** on Wednesday, July 13, 2011 at 12:29pm.

This is what my teacher gave us I guess he want us to figture out the question.

cost/mile 0.08 normal distribution

means=.08

standard deviation=0.2

Car life 5 uniform distribution( minmun=2, max=8

annual milage =900 triangular distribution(min=3700

most likely =9000

max=14500

annual cost= 3600

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