Posted by
**elizabeth6** on
.

This is what my teacher gave us I guess he want us to figture out the question.

cost/mile 0.08 normal distribution

means=.08

standard deviation=0.2

Car life 5 uniform distribution( minmun=2, max=8

annual milage =900 triangular distribution(min=3700

most likely =9000

max=14500

annual cost= 3600