Posted by **renee** on Wednesday, July 13, 2011 at 11:32am.

Solve the equation. If necessary, round to thousandths.

3^(2x + 1) = 27

- algebra 2 -
**renee**, Wednesday, July 13, 2011 at 11:33am
my bad supposed to say algebra 2

- algebra 21 -
**Reiny**, Wednesday, July 13, 2011 at 1:03pm
3^(2x+1) = 3^3

2x+1 = 3

2x=2

x=1

- algebra 21 -
**Max**, Wednesday, July 13, 2011 at 1:05pm
Substitute (2x + 1) for y.

3^y = 27

y = 3

Back-substitute.

2x + 1 = 3

x = 1

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