Wednesday

July 30, 2014

July 30, 2014

Posted by **pavatharani** on Wednesday, July 13, 2011 at 10:36am.

- physics -
**bobpursley**, Wednesday, July 13, 2011 at 10:39amfinal KE=initialPE-initial KE

1/2 m v^2=mgh-1/2 m u^2

1/2m(9u^2-u^2)=mgh

solve for h.

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