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December 18, 2014

December 18, 2014

Posted by **maria** on Wednesday, July 13, 2011 at 8:15am.

- trig -
**Reiny**, Wednesday, July 13, 2011 at 8:36amI will assume you meant

(tan^2 Ø + 1)/sec Ø = sec Ø

by the Pythagorean identity

tan^2Ø + 1 = sec^2 Ø , so ....

LS = sec^2 Ø/secØ

= secØ

= RS

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