Solve the equation. If necessary, round to thousandths.
3^(2x + 1) = 27
3^?=27
3^3=27
drop the bases
2x+1=3
x=2
I believe Capreeca is wrong on this one.
2x+1=3
2x=2
x=1
To solve the equation 3^(2x + 1) = 27, we can start by recognizing that 3^3 = 27. Therefore, we can rewrite the equation as:
3^(2x + 1) = 3^3
Since the bases are the same, we can equate the powers:
2x + 1 = 3
Now, we can solve for x.
Subtract 1 from both sides of the equation:
2x = 3 - 1
2x = 2
Divide both sides of the equation by 2:
x = 2/2
x = 1
Therefore, the solution to the equation is x = 1.